find the sum of 50 multiples of 4 ?
Answers
Answered by
2
Explanation:
Multiples of
4
between
10
and
50
are
{
12
,
16
,
20
,
...
...
,
48
}
, and these form an arithmetic sequence with first term as
12
, common difference
4
and last term as
48
.
Let
48
be the
n
t
h
term and then as
T
n
=
a
1
+
(
n
−
1
)
d
, where
a
1
is first term and
d
is common difference and hence
48
=
12
+
(
n
−
1
)
4
gives us
n
=
10
and as sum of
n
terms of an arithmetic series is given by
S
n
=
n
2
(
2
a
1
+
(
n
−
1
)
d
)
and sum of all multiples of
4
between
10
and
50
is
10
2
(
2
⋅
12
+
9
⋅
4
)
=
5
(
24
+
36
)
=
5
⋅
60
=
300
Answered by
2
Answer:
200 this is answer this question
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