Math, asked by rama4526, 1 year ago

find the sum of 51 term of AP dot in which second and third term are 14 and 18 respectively

Answers

Answered by Anonymous
0

a2 = 14 and a3 = 18

Common difference = a3 - a2 = 18 - 14 = 4 = d

Now  

a2 = a+d=14  

a+4=14

a = 10

Now, sum of 51 terms

={51(2a+(50)d)}/2

={51(20+200)}/2

={51×220}/2

=51×110=5610

Hope this helps Uh!

Answered by Anonymous
0

\bf\huge\boxed{\boxed{\bf\huge\:Hello\:Mate}}}




\bf\huge Let\:a\:be\:first\:term\:and\:D\:be\:Common\:difference




\bf\huge a_{2} = 14 \:and\: a_{3} = 18




\bf\huge a + d = 14 , a + 2d = 18




\bf\huge By\:Solving\:Equation




\bf\huge d = 4 \:and\: a = 10




\bf\huge Substitute\: a = 10 , d = 4 \:and\: n = 51




\bf\huge S_{n} = \frac{N}{2}[2a + (n - 1)d]




\bf\huge S_{51} = \frac{51}{2}[2\times 10 + (51 - 1)\times 4]




\bf\huge = \frac{51}{2}[20 + 50\times 4]




\bf\huge = \frac{51}{2}(20 + 200)




\bf\huge = \frac{51}{2}\times 220




\bf\huge = 51\times 110




\bf\huge = 5610





\bf\huge\boxed{\boxed{\:Regards=\:Yash\:Raj}}}



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