Question

Find the Sum of 51 terms of an AP whose second and third terms are 14 and 18 respectively​

Answer 1

Difference between consecutive terms = d

So,
d = 18-14 = 4

Now,
a3 = a + 2d
18 = a + 8
a = 10

So,
a51 = a + 50 d
a 51 = 10 + ( 50 x 4 )
a 51 = 210

Answer 2

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