Question

Find the sum of 51 terms of the A.P. whose second term is 2 and the 4th term is 8.

Answer 1

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Answer 2

Answer:

$given... \\ a_{2} = 2 \\ a_{4} = 8 \\ too \: find \: = s_{15} \: \: \: \\ solve = \\ a + d = 2......eq1 \\ a + 3d = 8......eq2 \\ solve \: eq1 \: and \: eq2 \\ d = 3 \\ then... \\ s_{15} = \frac{15}{2} (2 \times ( - 1) + (15 - 1)3) \\ s_{15} = \frac{15}{2} ( - 2 + 42) \\ s_{15} = \frac{15}{2} (40) \\ s_{15} = 15 \times 20 \\ s_{15} = 300$

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