find the sum of 51 terms of the A.P whose second term is 2 and the 4th term is 2
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Answered by
1
becaus second term and fourth term pc an ap is same therefore common difference will be 0.hence 51 term will also be 2.
sum will be 102
Answered by
2
first term be a
common difference be d
second term =a + d
a+d =2.
a=2-d.
fourth term =a+ 3d
2=2-d+3d
2-2=2d
d=0/2
d=0
a=2-0
a=2
51 term
=a+50d
=2+0
51 term =2
sum of 51 terms =n/2(first term+ last term). (n=no.of terms)
=51/2(2+2)
=51/2×4
=51×2
=102
hope you got the answer if you are satisfied than pls mark it brainlist
common difference be d
second term =a + d
a+d =2.
a=2-d.
fourth term =a+ 3d
2=2-d+3d
2-2=2d
d=0/2
d=0
a=2-0
a=2
51 term
=a+50d
=2+0
51 term =2
sum of 51 terms =n/2(first term+ last term). (n=no.of terms)
=51/2(2+2)
=51/2×4
=51×2
=102
hope you got the answer if you are satisfied than pls mark it brainlist
onlyannu:
I'm not satisfied because your answer was wrong
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