Find the sum of
52 +10° +152 + ... +1052
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Answered by
4
Answer:
52+10+152+1052=214+1052=1266
Answered by
1
Sum of the First n Squares
The formula for finding the sum of the first n squares is given by n(n+1)(2n+1)6.
Step-by-step explanation:
Answer and Explanation: 1
The idea of solving this problem is we first get the sum of the first 105 squares. This is given by105(105+1)(2(105)+1)6=105(106)(211)6=391405."
12+22+32+4212+22+32+42 which is not included in the problem.
Hence, we subtract this from 391405.
391405−4(4+1)(2(4)+1)6=391405−4(5)(9)6=391405−30=391375.391405−4(4+1)(2(4)+1)6=391405−4(5)(9)6=391405−30=391375.
Therefore, 52+102+152+...+1052=391375."
52+102+152+...+1052=391375.
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