Math, asked by Thevesh, 11 months ago

Find the sum of
5² +10² +15² + ... +105²​

Answers

Answered by RDalal
8

Answer:

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Attachments:
Answered by pulakmath007
10

5² + 10² + 15² + . . . + 105² = 82775

Given :

5² + 10² + 15² + . . . + 105²

To find :

The sum

Formula :

 \displaystyle \sf{  {1}^{2}  +  {2}^{2}  +  {3}^{2}   + ... +  {n}^{2} =  \frac{n(n + 1)(2n + 1)}{6}  }

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

5² + 10² + 15² + . . . + 105²

Step 2 of 2 :

Find the value of the expression

 \displaystyle \sf{  {5}^{2}  +  {10}^{2}  +  {15}^{2}   + ... +  {105}^{2} }

 \displaystyle \sf{ =   {(5 \times 1)}^{2}  +  {(5 \times 2)}^{2}  +  {(5 \times 3)}^{2}   + ... +  {(5 \times 21)}^{2} }

 \displaystyle \sf{  =  {5}^{2}  \bigg[  {1}^{2}  +  {2}^{2}  +  {3}^{2}   + ... +  {21}^{2} \bigg] }

 \displaystyle \sf{  =  {5}^{2}  \times   \frac{21 \times (21 + 1) \times (42 + 1)}{6} }

 \displaystyle \sf{  = 25 \times   \frac{21 \times 22 \times 43}{6} }

 \displaystyle \sf{  = 25 \times   7 \times 11 \times 43 }

 \sf = 82775

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