Question

find the sum of 6 terms of a series:(2+5)+(2^2+8)+(2^3+11)+....

Answer 1

2+5,2^2+8,2^3+11+.....

7,4+8,6+11+....

7,12,17+.....

therefore,

first term is 7

common difference =>12-7=5

n=a+(n-1)d

n=7+(6-1)5..... ......n=6(given)

n=7+25

n=32

therefore 6th term is 32

hope it is the correct answer plz mark me as brailiest..