Question

Find the sum of 60 terms of the progression 3,5,7,....​

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

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★ Given :

A.P : 3, 5, 7........

First term (a) = 3

Common Difference (d) = 2

Number of terms (n) = 60

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★ To Find :

We have to find the sum of first 60 terms of the A.P.

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★ Solution :

We know the formula to find the sum.

$\Large{\implies{\boxed{\boxed{\sf{S_n = \frac{n}{2} \bigg(2a + (n -1)d \bigg)}}}}}$

______________[Put Values]

$\sf{→ S_n = \frac{\cancel{60}}{\cancel{2}} \bigg(2(3) + (60 - 1)2\bigg)} \\ \\ \sf{→S_n = 30 (6 + 59 \times 2)} \\ \\ \sf{→S_n = 30(6 + 118)} \\ \\ \sf{S_n = 30 \times 124} \\ \\ \sf{→S_n = 3720} \\ \\ \Large{\implies{\boxed{\boxed{\sf{S_n = 3720}}}}}$

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Answer 2

Answer:

hey frnd your answer is in attachment

Step-by-step explanation:

So frnd your final answer is 3720.

I hope u get your answer

thnx for asking

plzz mark as brainlist...