Question

Find the sum of 64 odd term

Answer 1

An odd integer is of the form 2m+1.

So we assume that 2m-3 , 2m-1 , 2m+1 and 2m+3 are the 4 consecutive odd numbers and their sum = 2m-3+2m-1+2m+1 +2m+3 = 8m which should be 64 as given:

8m = 64

m = 64/8 = 8

Therefore the required consecutive odd numbers are:

2m-3= 2*8-3 = 13

2m+1 = 2*8-1 = 15

2m+1 = 2*8+1 = 17

2m+3 = 2*8+3 = 19.