Question

Find the sum of a digit of a smallest number which when divide by 16,24,30 and 36 leaves remainder 8,16,22 and 28 respectively but exactly divide by 7

Answer 1

Answer:

Since the number when divided by 18 gives a remainder of 8, it means that the the number would be of format

18K+8

in which 18K part is fully divided and leaves no remainder while 8 remains undivided.

Seeing this if the number type of 18K+8 is divided by 9 the remainder remains 8 and thus the digit sum of the number should also be 8.

Thus by going through the given set of option we can figure out the one which totals to

Step-by-step explanation:

NOTE: In this we have considered 18 because this is easy and most suitable to figure out and saves the hassle of taking LCM and appluing remainder theorm into it. Because if we take 15 as a format, It is number divisible by 3 and 5 which are both smaller than 8

And in case of 24 it has factors of 2,3,4,6,8 and thus might not leave a remainder in we divide the format of 24K+8 by 2,4 or 8.

Thus 18K+8 is most suitable one.

Thank You !

Answer 2

Step-by-step explanation:

10 answer in this question