find the sum of a first 31 terms in an AP
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0
Answer:
where is the ap
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Answered by
1
Answer:496
Step-by-step explanation:
a=1, n=31, d=2-1 ,3-2.=1
Sn=n/2(2a+(n-1)d)
=31/2(2*1+(31-1)1)
=31/2(2+30)
=31/2(32)
=31(16)
Sn=496
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