Question

Find the sum of additive inverse and multiplicative inverse of 7/3

Answer 1

Answer:

the additive inverse = -7/3

the multiplicative inverse = 3/7

-7/3 + 3/7

-49+9/21

-40/21

Answer 2

Answer:

$\frac{-40}{21}$ is the sum of additive inverse and multiplicative inverse of $\frac{7}{3}$ .

Step-by-step explanation:

Explanation:

Additive inverse - To obtain a result equal to 0, additive inverse merely entails changing the number's sign and adding it to the initial number.

Multiplicative inverse - A number multiplied by another so that the result is 1 is said to be a number's multiplicative inverse.

Step 1:

So, the additive inverse of $\frac{7}{3}$  is  $\frac{-7}{3}$

and multiplicative inverse of $\frac{7}{3}$ is $\frac{3}{7}$.

Therefore, the sum of additive inverse and multiplicative inverse = $\frac{-7}{3}$ +$\frac{3}{7}$

⇒ $\frac{-49 + 9}{21}$ =  $\frac{-40}{21}$

Final answer:

Hence, the sum of additive inverse and multiplicative inverse of $\frac{7}{3}$ is$\frac{-40}{21}$.

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