Question

Find the sum of additive inverse and multiplicative inverse of 11.​

Answer 1

♣ Qᴜᴇꜱᴛɪᴏɴ :

Find the sum of additive inverse and multiplicative inverse of 11.​

♣ ᴀɴꜱᴡᴇʀ :

$\huge\boxed{\sf{\dfrac{-120}{11}}}$

♣ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴꜱ :

Note :

Additive inverse of any number is to do subtraction

Multiplicative inverse of any number is to do division

*The multiplicative inverse of a number for any n is simply   1/n*

Additive inverse of 11 = -11

Multiplicative inverse of 11 = $\sf{\dfrac{1}{11}}$

Sum of additive inverse and multiplicative inverse of 11 = -11 + $\sf{\dfrac{1}{11}}$

Solve -11 + $\sf{\dfrac{1}{11}}$ :

$\sf{\dfrac{-11}{1}}$ + $\sf{\dfrac{1}{11}}$

= $\sf{\dfrac{-121}{11}}$ + $\sf{\dfrac{1}{11}}$

= $\boxed{\sf{=\dfrac{-120}{11}}}$

Answer 2

Answer:

$\boxed{= \frac{-120}{11}}$

Step-by-step explanation:

⇒ Additive inverse :

•  Additive inverse of a number is that number when added to it ,the result is zero.

•  Additive inverse of a number "x" = "-x"

    →  Additive inverse of 11 = -11

⇒ Multiplicative inverse :

• Multiplicative inverse of a number is its reciprocal.

• Multiplicative inverse of "x" = "1/x"

    → Multiplicative inverse of 11 = 1/11

⇒ Sum of additive inverse and multiplicative inverse of 11 :

            $= -11+\frac{1}{11} \\\\ = (-11 \times \frac{11}{11}) +\frac{1}{11} \\\\ =\frac{-121}{11} +\frac{1}{11} \\\\ = \frac{-121+1}{11} \\\\ =\frac{-120}{11}$