find the sum of all 10 term of A.P whose n term is given by 5n-3
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hope this helps u
if we subsuit n =1,2 the result will the term 1,2
a₁ = 5*1-3= 5-3= 2
a₁₀= 5*10-3=50-3=47
we will use the formula sn= n/2(first term+last term )
s10 = 10/2 ( 2+47)
= 5*49
s10 = 245
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