find the sum of all 11 terms of A.P. whose midle term is 30
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Answer:
Sum of all 11 terms = 330
Explanation:
The AP has 11 terms. Hence, the middle term is the sixth term.
Given: Sixth term = 30
Let "d" be the common difference of the AP.
Hence the 11 terms of the AP may be written as:
30 - 5d, 30 - 4d, 30 - 3d, 30 - 2d, 30 - d, 30, 30 + d, 30 + 2d, 30 + 3d, 30 + 4d and 30 + 5d
Sum of these 11 terms = 30 + 30 + ...11 times
= 30*11
= 330
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