Find the sum of all 2 digits natural numbers which are divisible by 4?
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The two digits numbers which are divisible by 4 are
12,16,20,......96 in AP.
Sn = n/2(2a+(n -1)d)
Here a = 12 , d = 4.
tn = a + (n - 1) d
96 = 12 + ( n - 1) 4
84 = ( n - 1) 4
n - 1 = 21
∴n = 22
S22 = (22/2) (2×12 + (22 -1)4)
S22 = 11×[ 24 + 84]
S22 = 11×[ 24 + 84]
∴S22 = 1188.
12,16,20,......96 in AP.
Sn = n/2(2a+(n -1)d)
Here a = 12 , d = 4.
tn = a + (n - 1) d
96 = 12 + ( n - 1) 4
84 = ( n - 1) 4
n - 1 = 21
∴n = 22
S22 = (22/2) (2×12 + (22 -1)4)
S22 = 11×[ 24 + 84]
S22 = 11×[ 24 + 84]
∴S22 = 1188.
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