Find the sum of all 3 digit multiples of 7
Answers
Answered by
0
Answer:
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Step-by-step explanation:
Smallest 3 digit no. divisible by 7=
105 and the largest =994
An=105
D=7
n =?
An = A +(n-1)D
thus
994=105+(n-1)7
thus by solving further
n = 128
now ,
Sn = n/2[A+An]
Sn =128/2[105+994]
thus,
Sn =770336
Thus the sum of all the 3 digit numbers divisible by 7= 770336
Answered by
0
Answer:
So , number of 3 digit numbers divisible by 7 is 128. Substitute 1.=105 by Q=7, 2.994 by Q=128.So,the sum of all 3 digit numbers divisible by 7 is 70336.
Step-by-step explanation:
Shortcut
First divide 7 by 100 . The remainder will be 2.
Step 1 = Subtract 2 from 7 . 7-2=5
Step 2= Add the result 5 to 100 . 100+5=105.
105 is the first 3 digit number divisible by 7 .
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