Find the sum of all 3 digit natural
numbers, which are divisible by 8.
Answers
Answered by
5
Answer :-
67,200
Explanation:-
The 3 digit number which is divisible by 8 are :-
104, 112 , 120 .............992.
The numbers are in A. P
The numbers are in A. Pso,
a = 104
a = 104 d = 112 - 104
a = 104 d = 112 - 104d = 8
a = 104 d = 112 - 104d = 8l = 992
First we have to find the number of terms,
→
→
→
→
→
→
→
Now,
By using sum formula :-
Put the given value,
→
→
→
→
hence, The sum of 3 digit number which are divisible by 8 is 67,200.
Similar questions