Math, asked by zaid4540, 10 months ago

Find the sum of all 3 digit natural numbers , which are multiples of 11

Answers

Answered by sowndarya12

1

Answer:

44550

Step-by-step explanation:

tn=a+(n-1)d tn=990 a=110 d=11 tn = 81

Sn=n/2 (a+l) Sn=44550

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