Find the sum of all 3 digit natural numbers which are divisible by 11
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nth term =an =990
a= 110
an = a + (n -1)d
990= 110 + (n-1) 11
880/11 = n-1
81= n
Sn =n/2 { 2a + (n-1)d}
S81= 81/2 {2×110 + (81-1)11}
= 81/2 {220 +880}
=81/2 { 1100}
=81×550
=44550
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