Question

find the sum of all 3 digit number divisible by 3​

Answer 1

Answer:

Find the sum of all three digit numbers divisible by 3 :-

• Smallest 3 digit number divisible by 3 a=102.
• Largest 3 digit number divisible by 3 an=999.
• Common difference d=3.
• Let the total number of 3 digit number be n.
• an=a+(n−1)d.
• 999=102+(n−1)×3.
• 999−102=(n−1)×3.
• 897=(n−1)×3.