find the sum of all 3 digit number which are divided by 7
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Answer:
All three-digit natural numbers which are divisible by 7 are
105,112,119,126,...,994 which are in AP with a=105,d=7,l=994
Let the number of these terms be n. Then,
a
n
=994
a+(n−1)d=994
105+(n−1)×7=994
n=128
Now, S
n
=
2
n
(a+l)
S
n
=
2
128
(105+994)=70336.
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