find the sum of all 3 digit numbers which leave the remainder 1 when divided by 4
JOVIAL1001ash1:
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dis is math question
s by mistake i have choosen eng
so plzz mention the subject properly frm nxt time
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AP: 101,105..........997
..a=101 ,d=4 , Last term=997
value of n = 225
Sum= 225/2(101+997)
= 225×549
=123525...
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