Question

find the sum of all 3 digit numbers which leaves the remainder 2 when divided by 4​

Answer 1

Answer:

let try

Step-by-step explanation:

102,106,110,114,118,122,126,130,134,138,142,146,150,154,158,162,166,170,174,178,182,186,190,194,198,202,...............998

here a=102 d=4,last term l=998,n=20

now S=n/2(a+l)

=10(102+998)

=11000