Question

Find the sum of all 4 digit number which are divisible by 29

Answer 1

Answer:

FOR I GOES FROM 1 TO 9

FOR J GOES FROM 0 TO 9

FOR K GOES FROM 0 TO 9

FOR L GOES FROM 0 TO 9

IF ( ( (1000*I+100*J+10*K+L) MOD 29) = 0 ) AND ((I+J+K+L)=29) THEN

OUTPUT I,J,K,L

NEXT L

NEXT K

NEXT J

NEXT I

4988

7598

7859

9686

9947

There are 5 such numbers.

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Answer 2

sorry I don't know that