Math, asked by deepikajdb61, 7 months ago

Find the sum of all 4−digit numbers that can be formed using the digit 1,3,5,7,9 


without repetition​

Answers

Answered by shrikanth308
1

Answer:

666600

Step-by-step explanation:

Total no. of digits are 5, i.e.,

n=5

Total no. of digits required is 4, i.e.,

r=4

Therefore,

No. of 4 digits no. that can be formed =nPr=5P4=1!5!=120

No. of times each digit will appear =5120=24

Sum of digits at unit place =24(1+3+5+7+9)=24×25=600

Sum of all numbers =600×1000+600×100+600×10+600=666600

Hence the sum off all 4 diit numbers is 666600.

Answered by amitnrw
2

Given :   four digit numbers that can be formed by the digits 1 3 5 7 9 without repetition ​

To Find :   sum of all such four digit numbers

Solution:

1 3 5 7 9

numbers can be formed = ⁵P₄  = 5!  = 120  numbers

At each place digit  will occur 120/5 = 24  time

Thousand place    100 place   Tens place   units place

Sum of Digits at each place = 24 ( 1 + 3 + 5 + 7 + 9)

= 24 ( 25)

= 600

Hence  sum of all four digit numbers

600 (1000) + 600(100) + 600(10) + 600(1)

= 600 ( 1000 + 100 + 10 + 1)

= 600 ( 1111)

= 666600

sum of all four digit numbers that can be formed by the digits 1 3 5 7 9 without repetition ​  is  666600

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