Math, asked by bajrang225, 10 months ago

find the sum of all angles of a (1)regular decagon (2) a regular 14 sided polygon​

Answers

Answered by yoonie
8

Decagon = 10 angles,

sum of all interior angles = 2n-4 x 90 (n = no of sides)

= 16 x 90 = 1440

14 sided polygon

= 2n -4 x 90

= 24 x 90

= 2160

Answer. 1440 + 2160 = 3600

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Answered by Anonymous
2

Answer:

Step-by-step explanation:

We knownthat sum of all angles of a polygon with

n sides =(2n-4)*90

(1) n=8

sum of angles=(2*8-4)*90

=(16-4)*90

=12*90

=1080

(2) n=14

sum of all angles=(2*14-4)*90

=(28-4)*90

=24*90

=2160

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