Math, asked by rickey004, 11 months ago

find the sum of all coefficients in the given polynomial

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Answered by nirbhaya2020
2

Let p(x) = a(n) x^n + a(n-1) x^(n-1) + ... + a(1) x + a(0).  

Then, p(1) = a(n) + a(n-1) + ... + a(1) + a(0), which is the sum of the coefficients.

So, the sum of the coefficients for (x-2)^6 (x-4)^2 + (x+1)^3 (x-2)^3 + (x+1)^2 (x-4)^3 equals  

(1-2)^6 (1-4)^2 + (1+1)^3 (1-2)^3 + (1+1)^2 (1-4)^3  

= 1 * 9 + 8 * -1 + 4 * -27  

= -107.

Answered by tejeswar184
2

Answer:

-107

I hope this answer may help you dear

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