Find the sum of all coefficients (including the constant term) in the expansion of (2x−12)^3
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0
Answer:
-30
Step-by-step explanation:
(2x-12)^3
=2x^3-12^3
=6x-36
So,coefficient of x = 6
constant term = -36
So,their sum = 6+(-36)
= 6-36
=-30
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