Math, asked by laurencatipon2, 8 days ago

find the sum of all counting numbers between 50 and 350 that have 1 as the last digit.​

Answers

Answered by XxitztoxicgirlxX
0

The sequence 51+61+71...+341 is an arithmetic progression.

⇒ To find the sum of n terms of an AP we use the formula.

⇒ Here, n=30,a=51 and d=10.

∴ S

n

=

2

n

[2a+(n−1)d]

∴ S

n

=

2

30

[2×51+(30−1)10]

∴ S

n

=15[102+290]

∴ S

n

=15×392

∴ S

n

=5880

Answered by pavitrandharmayat
0

Answer:

5880

The sequence 51+61+71...+341 is an arithmetic progression.

⇒ To find the sum of n terms of an AP we use the formula.

⇒ Here, n=30,a=51 and d=10.

∴ S

n

=

2

n

[2a+(n−1)d]

∴ S

n

=

2

30

[2×51+(30−1)10]

∴ S

n

=15[102+290]

∴ S

n

=15×392

∴ S

n

=5880

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