find the sum of all even integer 101 and 999
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all even integer no is 102
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1
“Sum of first 'n' even integers =
n(n+1)”
“Sum of all even integers between 101 and 999”
= (Sum of all even integers between 1 and 9999) – (Sum of all
even integers between 1 and 101)
“= 9999(9999+1) - 101(101+1)”
“= 9999(10000) - 101(102)”
“=99990000 – 10302 = 99979698”
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