Question

Find the sum of all even integers between 2 to 100 divisible by 2.​

Answer 1

Answer:

If we think about all odd integers between 2 and 100 which are divisible by 3 the first term of AP(a) is 3 and last one(t) is 99. The series will be-

3,9,15….,99

Total number of terms in AP is 17

The sum of an AP S=n(a+t)/2

Where a is first integer ,t is terminal integer and n is number of integers.

S=17(102)/2

S=17×51=867

Answer 2

Answer:

between 2-100

even no. starts from 4 to 98

Step-by-step explanation:

with the help of SUM FORMULA.

a= 4, d= 2, an= 98

a + (n -1 )d = 98

4 + (n- 1) 2 = 98

(n-1) = 24

n = 25

Sn = n/2(a + L)

Sn= 25/2 (4+ 98)

25/2(102)

25(51)

Sn = 1275