Find the sum of all even integers lying between 231 and 1999
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S= 232+234+236+ ————+ 1998
a= 232
d=2
L= 1998
a+(n-1)d= 1998
232 + 2n-2 =1998
2n= 1998+2-232 = 1768
n=1768/2 = 884
S = 884/2{ 232+1998}
= 442* 2230
a= 232
d=2
L= 1998
a+(n-1)d= 1998
232 + 2n-2 =1998
2n= 1998+2-232 = 1768
n=1768/2 = 884
S = 884/2{ 232+1998}
= 442* 2230
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