find the sum of all even number from 1 to 350
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Let's see first even no is 2 and last even no is 350
Then Sum of an A P is
S = (n*[2*a+(n-1)*d])/2
S is sum of first n terms of the A P where a is the first term and d is the common difference.
Here n = 350÷2= 175
d = 2(even number)
=>S = 175*[2*2+(175–1)*2]/2
=175*(176)=
=30800
Then Sum of an A P is
S = (n*[2*a+(n-1)*d])/2
S is sum of first n terms of the A P where a is the first term and d is the common difference.
Here n = 350÷2= 175
d = 2(even number)
=>S = 175*[2*2+(175–1)*2]/2
=175*(176)=
=30800
sahil205446:
thank
There is a small mistake in the answer.
to find out the value of n we should add 1 after dividing te last term with the common difference.
here n=176
the correct answer is 31152
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