Question

find the sum of all even numbers between 10 and 100 AP​

Answer 1

The first even number between 10 and 100 is 12 and the last even number is 98

The numbers are 12, 14, 16, ... 98

Difference between every two consecutive terms is 2.

This forms as AP with common difference = 2, first term = 12 and last term = 98

an = a + (n-1)d

98 = 12 + (n-1)2

n-1 = 43

n = 44

Sum of these terms = n/2[a+l] = 44/2[12+98] = 22(110) = 2420

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