find the sum of all even numbers less than 2010
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1
Explanation:
You asked what about the sum of even natural numbers. The sum of even natural numbers between 1 and 2n can be written as the sum of 2*i from i=1 to i=n. Factoring out the 2, it is equal to 2 times the sum of i from i=1 to n. Using the formula for the sum of consecutive numbers, we get that the sum of all even numbers from 1 to 2n equals n*(n+1).
In your case, the sum is through 100 which is 2*50. Therefore the sum of even number to 100 is 50*(51) = 2550
then you can go through it.
Answered by
0
Explanation:
n×(n+1)
n=2010
2010×(2010+1)
4042110
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