find the sum of all first n odd natural numbers
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n square is the sum of all first n odd natural numbers
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no.of terms=n
first term=1
common difference=2
sum of n odd terms (natural numbers)=
n/2 (2a+(n-1)d)
n/2 (2+(n-1)×2)
n/2 (2+ 2n-2)
n/2 (2n)
n/2× 2 (n)
n×n
n^2
first term=1
common difference=2
sum of n odd terms (natural numbers)=
n/2 (2a+(n-1)d)
n/2 (2+(n-1)×2)
n/2 (2+ 2n-2)
n/2 (2n)
n/2× 2 (n)
n×n
n^2
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