Question

find the sum of all integers between 10 an 500 divisible by 7

Answer 1

first term is 14
last term is 497
tn=a+(n-1)d
497=14+7n-7
490=7n
490/7=n
70=n

Answer 2

Answer:

Step-by-step explanation:ap=14,21......497

An=a+(n_1) d

497=14+(n_1)7

483/7=n_1

69+1=n

7o=n

S7o=70/2[2*14+(70_1)7]

S70=35[28+483]

S70=35*511

S70=17885