Question

Find the sum of all integers between 100 and 200 that are divisible by 6

Answer 1

Answer:

2550

Step-by-step explanation:

Use AP formula,

The first no. divisible by 6 is 102

The last no. divisible by 6 is 198

a = 102

an = 198

d = 6

an = a + (n - 1)d

198 = 102 + (n - 1)d

96 = 6(n - 1)

n - 1 = 16

: n = 17

Sn = n/2(a + an)

S17 = 17/2(102 + 198)

S17 = 17/2 * 300

:S17 = 2550

Answer 2

Step-by-step explanation:

the number which are divisible by 6 is 102,108,114,120,126.................198

here,a=102, d=6, an=198

an=a+(n-1)d

198=102( n-1)6

198-102=(n-1)6

96÷6=(n-1)

16=n-1

n=17

sn=n/2{2a+(n-1) d

sn=17) 2{2×102(17-1) 6}

sn=17/2(204+96)

sn=17/2(300)

sn=17×150

sn=2550

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