find the sum of all integers between 250 and 750 which are divisible by 11
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Answer:
23023
Step-by-step explanation:
numbers dvisible by 11 btn 250 and 750 are
253+264+275+.....+748
11(23+24+....+68)
68=23+(n-1)1. (a+(n-1)d)
68=23+n-1
69=23+n
n=69-23=46
sum=n/2(first+last)
=46/2(23+68)
=23(23+68)
=23×91
=2093
sum=2093×11=23023
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