Question

Find the Sum of all integers between 3 and 99 divided by 3​

Answer 1

Answer:

Step-by-step explanation: 3,6 9...... 99

a=3

d=6-3=3

n=33

Sn=n/2{2a+(n-1)d}

33/2{2×3+(33-1)3}

=33/2{6+22(3)}

=33/2{6+66}

=33/2(72)

=33(36)

=1188