find the sum of all Integers of 3 digits which are divisible by 7
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Answer:
128
Explanation:
so basically the first 3 digit term which gets divided by 7 is 105
i.e A.P is 105,112,119......994
i.e last term is 994
therefore , common difference=7
tn= t1+(n-1)d. formula from A.P
994=105 + (n-1) 7
994= 105 +7n-7
7n=994-98
7n=896
n=128
therefore 128 3 digit terms can be divided by 7
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