Find the sum of all multiple of 3 natural number between 1 to 100
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2
Answer:
Sn = 1683
Step-by-step explanation:
3 , 6 , 9 ....................... 99
a = 3
d = 6 - 3 = 3
an = 99
n = ??
Sn = ??
an = a + (n - 1) d
99 = 3 + (n - 1)3
99 = 3 + 3n - 3
3n = 99
n = 33
Sn = n [2a + (n - 1)d]
2
Sn = 33 [2*3 + (33 - 1) 3]
2
Sn = 16.5 [6 + 96]
Sn = 16.5 * 102
Sn = 1683
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