Question

find the sum of all multiple of 3 upto 100​

Answer 1

Solution:

3,6,9,....,99 are multiple of 3 upto 100

This is in A.P.

first term (a) = 3

common difference (d)

= a2-a1

= 6-3 = 3

$a_{n}=a+(n-1)d$

$a_{n}=99$

=> 3+(n-1)3=99

divide each term by 3 , we get

=> 1 + n - 1 = 33

=> n = 33

Now ,.

Sum of 33 terms Sn =n/2[a+an]

= (33/2)[3+99]

=(33/2)×102

=33 × 51

= 1683

Therefore,

Sum of all multiples of 3 upto

100 = 1683

••••

Answer 2

Answer:

1683 is the CORRECT ANSWER

Step-by-step explanation:

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