Question

find the sum of all multiples between 100 and 500 which are divisible by 5​

Answer 1

Answer:

23700

Step-by-step explanation:

a=105, nth= 495

nth= a+(n-1)d

495= 105+(n-1)5

390=(n-1)5

78=(n-1)

or, n=79

Sn= n/2×(a+l) where l= last term of the Ap

Sn= 79/2×(105+495)

Sn=79/2×600

Sn= 79×300

Sn= 23,700

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