Find the sum of all multiples of 13 lying between 1301 and 1700.
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194350
Step-by-step explanation:
here we have range from 1301 to 1700; by dividing we can easily find out that first term in this range divisible by 13 is 1313 and last term we can find out by dividing the last value (i.e. 1700 in this case) by 13 and subtracting remainder from the dividend, thus it comes out to be 1690
Now we will have,
- a(i.e. first term) = 1313
- common difference(d) = 13
- last term (L)= 1690
Now, to apply the formula of summession of series we need the number of terms lying in this range, we can easily find out that by applying formula
Nth term= a+(n-1)d
Or 1690 =1313+(n-1)13
Or 1690-1313=(n-1)13
Or 1677/13=(n-1)
Or 129 = n-1
therefore n = 130
Thus, now we have
- a(first term)= 1313
- d(common difference)= 13
- last term(L) = 1690
- & total no. of terms in this range(n)= 130
Thus we can easily apply formula
Sum of nth term= {n(a+L)}/2
Or {130(1313+1677)}/2
Or {130×2990}/2
Or 388770/2
= 194350 Answer
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