Find the sum of all multiples of 3 between 50 and 100
Answers
Step-by-step explanation:
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like:
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like:
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like: 3, 6, 9, 12,…………., 96, 99
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like: 3, 6, 9, 12,…………., 96, 99
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like: 3, 6, 9, 12,…………., 96, 99 So, we have the first term as 3, common difference as 3 and number of terms as 33, just put them into the formula S= n(2a + (n-1)d)/2 where n=number of terms, a=first term and d=common difference, to get the answer as 1683.
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like: 3, 6, 9, 12,…………., 96, 99 So, we have the first term as 3, common difference as 3 and number of terms as 33, just put them into the formula S= n(2a + (n-1)d)/2 where n=number of terms, a=first term and d=common difference, to get the answer as 1683.
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like: 3, 6, 9, 12,…………., 96, 99 So, we have the first term as 3, common difference as 3 and number of terms as 33, just put them into the formula S= n(2a + (n-1)d)/2 where n=number of terms, a=first term and d=common difference, to get the answer as 1683. In case you want to know how to arrive at this formula, put it in the comments and i’ll give you the derivation but i suggest you try it on your own, its really easy.
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like: 3, 6, 9, 12,…………., 96, 99 So, we have the first term as 3, common difference as 3 and number of terms as 33, just put them into the formula S= n(2a + (n-1)d)/2 where n=number of terms, a=first term and d=common difference, to get the answer as 1683. In case you want to know how to arrive at this formula, put it in the comments and i’ll give you the derivation but i suggest you try it on your own, its really easy.
This requires that you know how to calculate the sum of an arithmetic progression(an A.P.). Its easy to see that there are 33 multiples of 3 between 1 and 100 as 3*33=99 which is the nearest multiple of 3 less than 100. The A.P. will look like: 3, 6, 9, 12,…………., 96, 99 So, we have the first term as 3, common difference as 3 and number of terms as 33, just put them into the formula S= n(2a + (n-1)d)/2 where n=number of terms, a=first term and d=common difference, to get the answer as 1683. In case you want to know how to arrive at this formula, put it in the comments and i’ll give you the derivation but i suggest you try it on your own, its really easy. HAPPY LEARNING !
Answer:
1275
Step-by-step explanation:
multiples of 3 between 50-100
51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99
sum of all multiples of 3=
51+54+57+60+63+66+69+72+75+78+81+84+87+90+93+96+99=1275