Find the sum of all multiples of 4lying between 0 and 100.
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Answer:
sum of all multiples of 4 is 1300 lying between 0 &100
Step-by-step explanation:
Ap = 4,8,12,..…100
a=4
d=8-4
•°•d=4
let Tn =100
Let the no.of multiples of 4 be 'n'
Tn=a+(n-1)d
=>100=4+(n-1)4
=>100=4+4n-4
=>100=4n
=>100/4=n
=>25=n
•°•n=25
Now,
Sn =n/2(a+l)
=> Sn=25/2(4+100)
=> Sn =25/2 ×104
=> Sn=25×52
•°• Sn= 1300
Sum of all multiples of 4 is 1300 lying between 0&100
hope it's helpful for you
Thanks
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