find the sum of all multiples of 5 lie between 1 and 100
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Answer:
Step-by-step explanation:
there are 19 terms in the sequence
hence sum = s19 = 19/2 [2(5) + (19-1)5]
= 19/2 [ 10+ 90]
= 19/2 [100]
= 19 * 50
= 950
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